[Python] zip(*[iter(s)]*n)
zip(*[iter(s)]*n) 1. A better syntax for explanation is that: zip(*[iter(s)]*n) is same as zip(*([iter(s)] * n)) 2. iter() is an iterator over a sequence (in this case, s). 3. [iter(s)] * n <==> [iter(s), iter(s), ... <n times>] : creates an array of iterators 4. zip() method takes a input parameter in form of zip(*args), meaning it can take zip(x), zip(x,x), zip(x,x,x) and so forth. 5. Combining this, we are just doing: zip(iter(s), iter(s), <repeated n times>) Resources: https://stackoverflow.com/questions/2233204/how-does-zipitersn-work-in-python